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-x^2-9x=2x-6
We move all terms to the left:
-x^2-9x-(2x-6)=0
We add all the numbers together, and all the variables
-1x^2-9x-(2x-6)=0
We get rid of parentheses
-1x^2-9x-2x+6=0
We add all the numbers together, and all the variables
-1x^2-11x+6=0
a = -1; b = -11; c = +6;
Δ = b2-4ac
Δ = -112-4·(-1)·6
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{145}}{2*-1}=\frac{11-\sqrt{145}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{145}}{2*-1}=\frac{11+\sqrt{145}}{-2} $
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